Q.

How we got the formula v+u/t=average velocity

Asked by soumya,
16 Jul '09 10:13 pm

Earn 10 points for answering

Answers (4)

1.

It is (v+u)/2 = average velocity (you wrote t in place of 2).
Before telling the derivation, let me tell you that this formula is correct only when the acceleration is constant.
Derivation:
Let u = initial velocity i.e. velocity at time 0
v = velocity at time t
S = displacement from time 0 to time t
a = acceleration
For constant acceleration:-
S = ut + 1/2 *at^2
Dividing both sides by t,
S/t = u + 1/2 * at
By definition, displacement/time is average velocity
Therefore
average velocity = u + 1/2 *at
= (2u + at)/2
= (u+at + u)/2
But v = u+at
Therefore average velocity = (v+u)/2

Answered by Knowledge Software, 17 Jul '09 12:13 am
Report abuse

Useful

(0)

Not Useful

(0)

Your vote on this answer has already been received

2.

The average velocity v of an object moving through a displacement (d) during a time interval (t) is described by the formula: v=d/t
where,
v = Average Velocity
d = displacement
t = time

Answered by Pardeep kapoor, 16 Jul '09 10:26 pm
Report abuse

Useful

(0)

Not Useful

(0)

Your vote on this answer has already been received

3.

Ask a teacher or refer ur physics book.
The real derivations are difficult to write down here.

Answered by Ashish Mishra, 16 Jul '09 11:25 pm
Report abuse

Useful

(0)

Not Useful

(0)

Your vote on this answer has already been received

4.

Report abuse

Useful

(0)

Not Useful

(0)

Your vote on this answer has already been received