Using your phone's internet browser
go to:  qna.rediff.com
Click and drag this link to
the Home icon in your browser.
Q.

A particle moving in straight line with a velocity defined by the equation V = 24(square of time) - 24(cube of time). What time it would take to reach its maximum acceleration?

Asked by jeniffer, 08 Jan '09 07:13 pm
  Invite a friend  |  
  Save  |  
 Earn 10 points for answering
Answer this question  Earn 10 points for answering    
4000 characters remaining  
  
    
Keep me signed inNew User? Sign up

Answers (3)

 
1.

1/3 sec . am I correct
Answered by ravindran sankaran, 08 Jan '09 07:57 pm

 
  
Report abuse
Useful
 (0)
Not Useful
 (0)
Your vote on this answer has already been received
2.

V = 24 t^2 - 24 t^3 Acceleration a = dV/dt = 24 * 2t - 24 * 3t^2 a = 48 t - 72 t^2 da/dt = 48 - 72 * 2t da/dt = 48 - 144 t For maximum a, da/dt = 0 48 - 144 t = 0 t = 48/144 = 1/3
Answered by Knowledge Software, 09 Jan '09 11:18 am

 
  
Report abuse
Useful
 (0)
Not Useful
 (0)
Your vote on this answer has already been received
3.

To reach Its max +acceleration it would take 1/3 seconds & from there it would decelerate & magnitude of deceleration increases with time
Answered by Naimisha, 08 Jan '09 10:30 pm

 
  
Report abuse
Useful
 (0)
Not Useful
 (0)
Your vote on this answer has already been received

Ask a Question

Get answers from the community

600 characters remaining

Related Answer

Q.
A

Yaar jab Cycle hai to cycle pe jao na paidal chalne ki jarurat kaya hai biwi dadte gi.............more

Answered by Madhumita Yadav