Q.

A stone is thrown upward with an initial velocity 40m/s.taking g=10m/s. find the maximum height reached by the stone?

Asked by cdit,
06 Aug '11 06:08 pm

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Answers (4)

1.

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2.

First of all the Unit of 'g' given by you ie m/s is wrong.Aassuming it is 10 m/sec/sec (10m/secondsquare) and no wind resistance and vertical thrown,the stone will go to the maximum height of 80 metres.The formula used is V^2=U^2+2gh; Here V=0(final velocity),U=10(initial velocity),g= -10(due to opposite direction of throw and acceleration due to gravity),h=height,Thus 0=40x40-2x10xh gives h=80m

Answered by M Singh, 06 Aug '11 06:30 pm
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3.

Since you want to find the maximum height it reaches, the highest point of any object when thrown upwards has a final velocity of 0m/s because all the kinetic energy in the object is used to overcome the gravitational potential energy in it.

Since the ball is travelling upwards, the acceleration due to gravity has a negative value. Because this quantity is a vector, and as the ball goes up, it is moving in a direction opposite the acceleration due to gravity.

Since the ball is travelling upwards, the acceleration due to gravity has a negative value. Because this quantity is a vector, and as the ball goes up, it is moving in a direction opposite the acceleration due to gravity.

Source: y

Answered by rajesh, 06 Aug '11 06:12 pm
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4.

What about wind speed value? rain? height above sea level? angle at which it was thrown? any bird was there in path?

Answered by Insane Guy, 06 Aug '11 06:11 pm
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