Q.

Calculate the number of water molecule and number of O and H in drop of water ?

Asked by Ramjee Sinha,
13 May '07 12:27 pm

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Answers (3)

1.

The volume of one drop of water will be approximately 0.05 mL or Cubic Centimeters. The density (Specific Gravity) of water is almost 1g per CC. Thus the weight of one drop of water will be 0.05g.

Gram Molecular weight of water is 18g. The number of water molecules in 18g of water is 6.023 x 10 to the power of 23 molecules, which is the Avogadro number. (= 602,300,000,000,000,000,000,000 molecules)

Hence the number molecules present in one drop of water will be 1.673 x 10to the power of 21(16,730,000,000,000,000,000,000 molecules)

The molecular formula of water is H2O. That means each water molecule is composed of 2 H (Hydrogen) atoms and 1(one) O ( Oxygen) atom. Thus the number of H atoms in one drop of water will be twice the number of water molecules, while the number of O atoms will be the same as the number of water molecules.

Answered by manepalli hariprasad, 19 Jun '07 07:31 am
Gram Molecular weight of water is 18g. The number of water molecules in 18g of water is 6.023 x 10 to the power of 23 molecules, which is the Avogadro number. (= 602,300,000,000,000,000,000,000 molecules)

Hence the number molecules present in one drop of water will be 1.673 x 10to the power of 21(16,730,000,000,000,000,000,000 molecules)

The molecular formula of water is H2O. That means each water molecule is composed of 2 H (Hydrogen) atoms and 1(one) O ( Oxygen) atom. Thus the number of H atoms in one drop of water will be twice the number of water molecules, while the number of O atoms will be the same as the number of water molecules.

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