Q.

A peacock is sitting on the top of a pillar which is 9 m high. From a point 27 m away from the bottom of the pillar, a snake is coming to its hole at the base of the pillar.Seeing the snake the peacock pounces on it. If their speeds are equal at what distance from the hole is the snake caught?

Asked by ankit shivam,
02 Dec '11 02:26 pm

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Answers (6)

1.

Suppose peacock pounces making an angle theta with the vertical with a speed v and snake is also coming horizontally with speed v as given in question. Let t be the time taken.

Their relative velocity in horizontal direction = v+vsintheta and relative distance covered = 27 m

so, (v + vsintheta).t = 27..................(1)

Their relative velocity in vertical direction = vcostheta and relative distance covered = 9 m

so, (vcostheta).t = 9.....................(2)

Dividing these two : (1+sintheta)/costheta = 27/9

...more

Answered by Tanupriya, 02 Dec '11 02:29 pm
Their relative velocity in horizontal direction = v+vsintheta and relative distance covered = 27 m

so, (v + vsintheta).t = 27..................(1)

Their relative velocity in vertical direction = vcostheta and relative distance covered = 9 m

so, (vcostheta).t = 9.....................(2)

Dividing these two : (1+sintheta)/costheta = 27/9

...more

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3.

Intresting qns but realy forgotten the applications of hight & distance

Answered by sushil trivedi, 02 Dec '11 02:33 pm
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4.

27+9=36. 36/2=18. ye to relative velocity se related. after some mind calculation i get answer was ummmmhh . this one 9m below hole. dono ko relatively 18m chalna hai na. (9)

Answered by ambuj kumar, 02 Dec '11 02:29 pm
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5.

Will solve this without trigonometry ( I'm in 8th standard)

Let AB be the pillar of height 9 meter. The peacock is sitting at point A on the pillar and B is the foot of the pillar. (.. AB = 9)

Let C be the position of the snake which is at 27 meters from B. (.. BC = 27 and ABC = 90)

As the speed of the snake and of the peacock is same they will travel the same distance in the same time....................................

Now take a point D on BC that is equidistant from A and C. (Please note that snake is moving towards the pillar and hence B-D-C)

Hence by condition 1 AD = DC = y (say)

Take BD = x

...more

Answered by Nauty, 02 Dec '11 02:26 pm
Let AB be the pillar of height 9 meter. The peacock is sitting at point A on the pillar and B is the foot of the pillar. (.. AB = 9)

Let C be the position of the snake which is at 27 meters from B. (.. BC = 27 and ABC = 90)

As the speed of the snake and of the peacock is same they will travel the same distance in the same time....................................

Now take a point D on BC that is equidistant from A and C. (Please note that snake is moving towards the pillar and hence B-D-C)

Hence by condition 1 AD = DC = y (say)

Take BD = x

...more

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