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Q.

1. Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?

Tags: years, money, relationships
Asked by Swarup vaidya, 25 Apr '12 11:26 am
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1.

2.2 times
Answered by Anil K Chugh, 25 Apr '12 12:52 pm

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2.

Ask him directly his present age. When he survives for 8 years, ask once again his age at that time!
Answered by dinkar shetty, 25 Apr '12 02:37 pm

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3.

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8. ...more
Answered by Ataur Rahman, 25 Apr '12 11:28 am

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4.

2..
Answered by Dev Shah, 25 Apr '12 11:27 am

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